Question

A sample containing 1.80 moles of ne gas has an initial volume of 6.00 l. What is the final volume of the gas, in liters, when each of the following changes occurs in the quantity of the gas at constant pressure and temperature? A leak allows one-half of the ne atoms to escape.

Answer 1

When the amount of Ne gas is halved from 1.80 moles to 0.90 moles at constant pressure and temperature, the volume of the gas also halves, resulting in a final volume of 3.00 liters.

Step-by-step explanation:

When a gas undergoes a change where pressure and temperature are held constant, the volume of the gas is directly proportional to the number of moles of the gas present according to Avogadro's law. This is often summarized as V1/n1 = V2/n2, where V represents volume and n represents moles. If the sample containing 1.80 moles of Ne gas initially has a volume of 6.00 L and then experiences a leak that allows one-half of the Ne atoms to escape, the final number of moles of Ne will be 1.80 moles / 2 = 0.90 moles.

Applying Avogadro's law:

Initial volume / Initial moles = Final volume / Final moles

6.00 L / 1.80 moles = Final volume / 0.90 moles

Therefore, Final volume = (6.00 L * 0.90 moles) / 1.80 moles = 3.00 L

So, the final volume of the Ne gas, after losing half of its atoms, will be 3.00 liters.