Question

A local service organization is wrapping gifts at the mall to raise money for charity. Yesterday, they wrapped 29 small gifts and 29 large gifts, earning a total of 232. Today, they wrapped 29 small gifts and 46 large gifts, and earned 334. How much did they charge to wrap the gifts?

Answer 1

The local service organization charged $2 to wrap a small gift and $6 to wrap a large gift, which was determined by setting up a system of equations from the earnings of two separate days and solving for the charges per gift.

Step-by-step explanation:

The question asks us to calculate how much the local service organization charged for wrapping small and large gifts based on the earnings from two separate days. To find this, we can set up a system of equations using the given information. Let "s" represent the charge for wrapping a small gift, and "l" represent the charge for wrapping a large gift.

From the first day, the equation is 29s + 29l = 232. On the second day, the equation is 29s + 46l = 334. Now we have a system of equations:

• 29s + 29l = 232 (1)
• 29s + 46l = 334 (2)

We can solve this system by subtracting equation (1) from (2) to eliminate "s" and find the value of "l":

1. Subtract equation (1) from equation (2): (29s + 46l) - (29s + 29l) = 334 - 232
2. This simplifies to 17l = 102
3. Divide by 17 to find the charge for a large gift: l = $6

Now, substitute l = 6 into equation (1) to find "s":

1. 29s + 29(6) = 232
2. 29s + 174 = 232
3. Subtract 174 from both sides: 29s = 58
4. Divide by 29 to find the charge for a small gift: s = $2

Therefore, the charge for wrapping a small gift is $2, and the charge for wrapping a large gift is $6.