Question

Consider the following generic reaction: a 2b→c 3d, with Δh = 104 kj. Determine the value of Δh for each of the following related reactions?

Answer 1

To determine the value of ΔH for each of the related reactions, we use the concept of Hess's Law. By breaking down the given reaction into smaller steps and finding the enthalpy change for each step, we can add up the enthalpy changes to find the overall enthalpy change for the reaction.

Step-by-step explanation:

In order to determine the value of ΔH for each of the related reactions, we need to use the concept of Hess's Law. Hess's Law states that the overall enthalpy change of a reaction is equal to the sum of the enthalpy changes of its individual steps or reactions.

So, to determine ΔH for each related reaction, we need to break down the given reaction into smaller steps and find the enthalpy change for each step. Then, we can add up the enthalpy changes to find the overall enthalpy change for the reaction.

Let's denote the given reaction as Reaction 1: a 2b → c 3d with ΔH = 104 kJ.

Now, let's consider a related reaction, Reaction 2: x 2y → 2a.

To find ΔH for Reaction 2, we can use the concept of Hess's Law and the given information as follows:

1. Reverse Reaction 1 to get -a 3d → -a 2b with ΔH = -104 kJ.
2. Multiply the reversed reaction by x/(-a) to get -ax 3d → -ax 2b with ΔH = (-104 kJ) * (x/(-a)).
3. Double the reversed reaction to get 2(-ax) 3d → 2(-ax) 2b with ΔH = 2 * ((-104 kJ) * (x/(-a))).
4. Finally, divide the above reaction by 2 to get (-ax) 3d → (-ax) 2b with ΔH = ((-104 kJ) * (x/(-a))).

So, ΔH for Reaction 2 is ((-104 kJ) * (x/(-a))).