The original has dimensions 16 in, 12 in and 20 in.
The image has dimensions 3 in, 4 in and 5 in.
We need to find the perimeter of both triangles and then compare them.
The perimeter of a triangle is given as:
P = a + b + c
where a, b, c are the three sides of the triangle
Therefore, the perimeter of the original is:
P = 16 + 12 + 20 = 48 in
The perimeter of the image is:
p = 3 + 4 + 5 = 12 in
By comparing these two perimeters, we can see that the perimeter of the original is 4 times that of the image.
So the image's perimeter is 1/4 that of the original. (Option B)