Final answer:
To solve the algebra problem, we set two equations and solve them to find that the two numbers satisfying the conditions of having a sum of 29 and one number being 3 more than the other are 13 and 16.
Step-by-step explanation:
The question presents a simple algebra problem where two numbers have a sum of 29 and one number is 3 more than the other. To find the numbers, we can set up two equations based on the information given:
- Let x be the first number.
- Then the second number would be x + 3 because it is 3 more than the first number.
- According to the problem, x + (x + 3) = 29.
- Solving for x gives us x + x + 3 = 29 which simplifies to 2x + 3 = 29.
- Subtracting 3 from both sides of the equation gives us 2x = 26.
- Dividing both sides by 2, we find that x = 13.
- Therefore, the second number is x + 3 = 13 + 3 = 16.
So the two numbers that satisfy the conditions are 13 and 16. This corresponds to option a) 13, 16.