Final answer:
The car in the graph is speeding up constantly if it shows a consistent increase in velocity over the first 6 seconds. Car A is traveling faster at the checkpoint than Car B since it starts from rest with a positive, constant acceleration. Objects can accelerate by speeding up, slowing down, or changing their direction of travel.
Step-by-step explanation:
Analyzing the car speed graph for the first 6 seconds, the car is speeding up constantly if its velocity is increasing in a straight line, which indicates a positive, constant acceleration. This can be identified by a slope that continually moves away from the zero-velocity line on a distance-time graph or a straight line moving upwards on a velocity-time graph. The car would not necessarily be changing direction (unless the graph indicated a change in the sign of velocity), experiencing less friction, or climbing a steep incline based solely on the acceleration information.
Regarding two cars side by side where one car (Car A) starts from rest with a positive, constant acceleration and the other car (Car B) travels at a constant speed, reaching a checkpoint at the same time indicates that Car A would be traveling faster at the checkpoint. The proposed equation V = KV0, where K is a constant and V0 is the initial velocity of Car B, is not consistent with the experimental data if Car A starts from rest, as Car A's initial velocity is zero and the calculation for V would always result in zero, which does not represent the conditions described where Car A reaches a faster speed than Car B at the checkpoint.
When discussing acceleration, objects can accelerate by speeding up, slowing down, or changing direction. An object is not accelerating if the magnitude and the direction of velocity remain constant, which is to say, if an object is moving at a constant velocity in a straight path, it is not accelerating.