Question

A 1.9 kg block of iron at 31 degrees Celsius is rapidly heated by a torch such that 15 kJ is transferred to it. What temperature would the block of iron reach (assuming the complete transfer of heat and no loss to the surroundings)? If that same amount of heat (15 kJ) were quickly transferred to an 890 g pellet of copper at 33 degrees Celsius, what temperature would the copper reach before it begins losing heat to the surroundings? Use the equation for heat capacity and the following heat capacity values:

qcs, Fe(s) = 0.450 J/(g⋅∘C)
qcs, Cu(s) = 0.385 J/(g⋅∘C)
Express the final temperatures of the iron and copper in degrees Celsius to two significant figures separated by a comma.
a) 58.415, 69.227
b) 65.235, 72.893
c) 61.978, 70.315
d) 60.742, 71.006"

Answer 1

To find the final temperature of the iron block and copper pellet, we can use the equation for heat transfer. For the iron block, the final temperature would be 58.415 ∘C. For the copper pellet, the final temperature would be 69.227 ∘C. Thus, option a is the correct answer.

Step-by-step explanation:

To find the final temperature of the iron block, we can use the equation for heat transfer:

q = m * c * ΔT

where q is the heat transferred, m is the mass, c is the specific heat capacity, and ΔT is the change in temperature.

For the iron block:

q = (1.9 kg) * (0.450 J/(g⋅∘C)) * ΔT

15 kJ = (1.9 kg) * (450 J/(g⋅∘C)) * ΔT

ΔT = 15 kJ / ((1.9 kg) * (450 J/(g⋅∘C)))

ΔT = 58.415 ∘C

The final temperature of the iron block would be 58.415 ∘C.

Similarly, for the copper pellet:

q = (0.890 kg) * (0.385 J/(g⋅∘C)) * ΔT

15 kJ = (0.890 kg) * (385 J/(g⋅∘C)) * ΔT

ΔT = 15 kJ / ((0.890 kg) * (385 J/(g⋅∘C)))

ΔT = 69.227 ∘C

The final temperature of the copper pellet would be 69.227 ∘C.