Question

F(x) = x2 minus 5. Graph f(x).

Approximately where does f(x) cross the x-axis? Write your answer(s) as
an ordered pair(s).

Answer 1

To graph f(x) = x² - 5, solve x² - 5 = 0 to find x-intercepts, which are approximately (2.236, 0) and (-2.236, 0). The graph will be a U-shaped parabola crossing the x-axis at these points.

Step-by-step explanation:

To graph the function f(x) = x² - 5, you can start by plotting some points where x is a real number between 0 and 20. To find where the function crosses the x-axis, look for the values of x where f(x) is equal to 0. This means solving the equation x² - 5 = 0. Factoring this, we get (x - √5)(x + √5) = 0, which gives us two solutions for x: √5 and -√5. Therefore, the points where the function crosses the x-axis are approximately (2.236, 0) and (-2.236, 0), considering √5 is approximately 2.236. To complete the graph, you would plot additional points, and since it's a parabola facing upwards, the plot will be a U-shaped curve with the vertex at the point (0, -5).