Final answer:
To find the number of grams of phosphorus in 23.505 g of sodium phosphate, calculate the moles of sodium phosphate using its molar mass, and then use the molar ratio to find the grams of phosphorus.
Step-by-step explanation:
To calculate the number of grams of phosphorus in 23.505 g of sodium phosphate (Na3PO4), we need to find the molar mass of sodium phosphate and use it to convert grams to moles. The molar mass of sodium phosphate is calculated by adding the atomic masses of each element: (3 x atomic mass of Na) + atomic mass of P + (4 x atomic mass of O). Once we have the molar mass, we can use it to convert grams to moles using the formula moles = grams / molar mass. Finally, we can use the molar ratio between phosphorus and sodium phosphate to find the grams of phosphorus. The molar ratio is 1:1, so the number of grams of phosphorus is equal to the number of moles of phosphorus multiplied by the molar mass of phosphorus.
Given that the molar mass of Na3PO4 is 163.94 g/mol, and the atomic mass of P is 30.97 g/mol, we can calculate:
moles of Na3PO4 = 23.505 g / 163.94 g/mol = 0.1432 molgrams of phosphorus = 0.1432 mol x 30.97 g/mol = 4.432 g
Therefore, there are 4.432 grams of phosphorus in 23.505 g of sodium phosphate.