Question

A rectangular paperboard measuring 26 in long and 20 in wide has a semicircle cut out of it, as shown below. What is the perimeter of the paperboard that remains after the semicircle is removed? (Use the value 3.14 for pi, and do not round your answer. Be sure to include the correct unit in your answer)

Answer 1

To find the perimeter, first, we sum the three sides belonging to the rectangle.

`R=20+26+26=72in`

Then, we find half of the circumference of the circle knowing that its diameter is 20 inches.

`C=(\pi d)/(2)=(\pi\cdot20)/(2)=10\cdot3.14=31.4in`

At last, we sum both quantities.

`P=72+31.4=103.4in`

Hence, the perimeter is 103.4 inches.