Question

What is the equation of this circle in standard form? O(x-2)² + (y - 3)² = 36 O(x + 2)² + (y + 3)² = 6 O(x - 2)² + (y - 3)² = 6 O (x + 2)² + (y + 3)² = 36 -10 -9 -8 -7 -6 1 -2 -5 -6 -7 10 10 9 8 7 6 4. 1 2 3 4 5 9 10​

Answer 1

The equation of the circle graphed is (x + 4)² + (y + 5)² = 16

Determining the equation of the circle graphed

From the question, we have the following parameters that can be used in our computation:

The circle

Where, we have

Center = (a, b) = (-4, -5)

Radius, r = 4 units

The equation of the circle graphed is represented as

(x - a)² + (y - b)² = r²

So, we have

(x + 4)² + (y + 5)² = 4²

Evaluate

(x + 4)² + (y + 5)² = 16

Hence, the equation is (x + 4)² + (y + 5)² = 16