Question

Find the equation of the straight line that passes through the points -3, -5 and 2, -11. First, what is the slope?

Answer 1

From the given question

There are given that the two points:

`(-3,\text{ -5) and (2, -11)}`

Now,

(a)

For finding the slope, use the slope formula:

`m=(y_2-y_1)/(x_2-x_1)`

Then,

`\begin{gathered} m=(y_2-y_1)/(x_2-x_1) \\ m=\frac{-11_{}-(-5)_{}}{2_{}-(-3)_{}} \\ m=(-11+5)/(2+3) \\ m=-(6)/(5) \end{gathered}`

Hence, the slope of the given line is shown below:

`m=-(6)/(5)`