Question

946.32 g water X 1 mol H₂O / 18.015 g H₂O X 4 mol lemonade / 2 mol H₂O X 225.285 g lemonade / 1 mol lemonade

A. 400 g lemonade
B. 300 g lemonade
C. 450 g lemonade
D. 500 g lemonade

Answer 1

To find the mass of lemonade, we need to apply the given conversion factors. First, we convert the mass of water to moles of water using the molar mass of water (18.015 g/mol). Then, we use the ratio of moles of lemonade to moles of water (4 mol lemonade / 2 mol water) The mass of lemonade is 400 g.

Step-by-step explanation:

To find the mass of lemonade, we need to apply the given conversion factors. First, we convert the mass of water to moles of water using the molar mass of water (18.015 g/mol). Then, we use the ratio of moles of lemonade to moles of water (4 mol lemonade / 2 mol water) to convert from moles of water to moles of lemonade. Finally, we convert moles of lemonade to mass of lemonade using the molar mass of lemonade (225.285 g/mol). Using the given values: 946.32 g water x (1 mol H2O / 18.015 g H2O) x (4 mol lemonade / 2 mol H2O) x (225.285 g lemonade / 1 mol lemonade) = 400 g lemonade.

To find the mass of lemonade, we need to apply the given conversion factors. First, we convert the mass of water to moles of water using the molar mass of water (18.015 g/mol). Finally, we convert moles of lemonade to mass of lemonade using the molar mass of lemonade (225.285 g/mol). Then, we use the ratio of moles of lemonade to moles of water (4 mol lemonade / 2 mol water) The mass of lemonade is 400 g.