Question

Working together, it takes two different sized hoses 25 minutes to fill a small swimming pool. If it takes 45 minutes for the larger hose to fill the swimming poolby itself, how long will it take the smaller hose to fill the pool on its own?Do not do any rounding.

Answer 1

`(1)/(x)+(1)/(45)=(1)/(25)`

Where:

x = Time to fill the pool using the smaller hose

Solve for x:

`\begin{gathered} (1)/(x)=(1)/(25)-(1)/(45) \\ (1)/(x)=(4)/(225) \\ 4x=225 \\ x=(225)/(4) \\ x=56.25 \end{gathered}`

Answer:

56.25 minutes