Question

1. In the first step of the experiment, students are told that the 50 miles graduated cylinder should be filled with 43 1/5 misters of a liquid mixture. of the misure should be water, and of the cure should be of the unknown liquid. How many misters of each substance should be put in the graduated finder? Show all your calculations

2. Next students are told that the liquid mixture they created in the first step should be dided every into the four 25 militer graduated cylinders. How many militers of the liquid mixture should be put into each 25 milliliter cylinder. Show all your calculations.

3. In the final step, the four 25 milier graduated cylinders, each containing an equal amount of the liquid mixture, are lined up, and one drop of food coloring is added to the first cylinder. Students are then directed to transfer 2 militers of the colored solution from the first cylinder to the second cylinder, then transfer another 4 milli liters of the colored solution from the first cylinder to the third cylinder, and finally transfer 6 milli liters of the colored solution from the first cylinder to the fourth cylinder. The students will then analyze and compare the intensity of color of thesolutions in the four graduated cylinders. Do the instructions for the final step make sense? Explain your reasoing.

Answer 1

To determine the amounts of water and unknown liquid to put in a 50 milliliter graduated cylinder, we need to calculate them based on the given proportion. The equation x/y = 43 1/5/50 can be used to solve for x and y. The amount of water should be 1083y/250 milliliters, and the amount of the unknown liquid should be y milliliters.

Step-by-step explanation:

In the first step of the experiment, the students are instructed to fill a 50 milliliter graduated cylinder with a liquid mixture. The instructions state that the cylinder should be filled with 43 1/5 milliliters of the mixture, with a certain proportion of water and an unknown liquid. To determine how many milliliters of each substance should be put in the cylinder, we need to calculate the amounts based on the given proportion. Let's denote the amount of water as 'x' and the amount of the unknown liquid as 'y'. According to the instructions, the proportion is x:y, with x being the amount of water and y being the unknown liquid.

So, we have the equation: x/y = 43 1/5/50 To solve for x and y, we can cross multiply: 50 * x = (43 1/5) * y Converting the mixed number to an improper fraction, we have: 50x = (216/5) * y Next, we can simplify the equation by multiplying both sides by 5 to eliminate the fraction: (250/5)x = 216y Canceling the 5s on the left side: 50x = 216y Now, we can solve for x or y by substituting the value of the other variable. Let's solve for x in terms of y: x = 216y/50 Simplifying the fraction: x = 1083y/250 Therefore, the amount of water (x) in the 50 milliliter graduated cylinder should be 1083y/250 milliliters, and the amount of the unknown liquid (y) should be y milliliters.