Final answer:
The jogger's new velocity after accelerating at the same rate as the passing bus for 20.0 seconds would be +18.0 m/s, which is not one of the provided answer options.
Step-by-step explanation:
The question is asking to find the new velocity of a jogger who accelerates at the same rate as a bus that passes her. The bus accelerates from +20.0 m/s to +25.0 m/s in 10.0 s. To find the acceleration of the bus, we use the formula for acceleration (a) which is the change in velocity (Δv) divided by the time (t), so a = (Δv) / t. The change in velocity for the bus is 25.0 m/s - 20.0 m/s = 5.0 m/s. Since the bus took 10.0 s to accelerate, its acceleration is 5.0 m/s / 10.0 s = 0.5 m/s². Now, we apply this acceleration to the jogger for 20.0 s. The jogger's initial velocity is +8.0 m/s, so the final velocity (v_f) will be the initial velocity (v_i) plus the product of acceleration (a) and time (t), which is v_f = v_i + a*t. Therefore, the jogger's final velocity is 8.0 m/s + (0.5 m/s² * 20.0 s) = 8.0 m/s + 10.0 m/s = +18.0 m/s. This is not one of the provided answer options, so it seems there may be a mistake in the given choices or a misunderstanding of the question.