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-3(x-14)+9x=6x+42what does that equal? is it true or false

User Orthehelper
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1 Answer

17 votes
17 votes

We are given the following equation


-3\mleft(x-14\mright)+9x=6x+42

Let us solve the equation for x.

Step 1:

Multiply the term -3 with the terms in the parenthesis.


\begin{gathered} -3(x-14)+9x=6x+42 \\ -3x+42+9x=6x+42 \end{gathered}

Step 2:

Simplify the terms on the left-hand side of the equation


\begin{gathered} -3x+42+9x=6x+42 \\ 42+6x=6x+42 \end{gathered}

Step 3:

Combine the like terms together.


\begin{gathered} 42+6x=6x+42 \\ 42-42=6x-6x \\ 0=0 \end{gathered}

This means that this equation has an infinite number of possible solutions.

If you notice the left and right side of the equation are exactly the same.


42+6x=6x+42

This means that whatever value of x you put into this equation, the equation will always be satisfied.

Try substituting some values for x.


\begin{gathered} 42+6(1)=6(1)+42 \\ 42+6=6+42 \\ 48=48 \end{gathered}
\begin{gathered} 42+6(-2)=6(-2)+42 \\ 42-12=-12+42 \\ 30=30 \end{gathered}

Hence, the given equation has an infinite number of possible solutions.

User SudoPlz
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