Final answer:
The speed of the ball that is thrown from a tower 35m high and travels a distance of 60m horizontally is approximately 20.07 m/s.
Step-by-step explanation:
To calculate the speed of the ball, we need to find the vertical component of the velocity. The ball is thrown a distance of 60m horizontally, which means there is no change in the vertical position. Since the ball is thrown from a height of 35m, its initial vertical velocity is 0 m/s (no change in height). Therefore, the speed of the ball that is thrown is equal to the horizontal component of the velocity. Using the given information, we can use the formula for horizontal velocity, Vx = distance / time, to find the speed of the ball. The time it takes for the ball to travel the distance horizontally is the same as the time it takes for the ball to fall to the ground vertically. Therefore, we can calculate the time using the equation d = 1/2 * g * t^2, where g is the acceleration due to gravity. Solving for t gives us t = sqrt(2d / g). Substituting the values, we get t = sqrt(2 * 35 / 9.8) = 2.99 seconds. Now, we can find the horizontal component of the velocity using the formula Vx = distance / time = 60 / 2.99 = 20.07 m/s. Therefore, the speed of the ball that is thrown is approximately 20.07 m/s.