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John was collecting aluminum cans for recycling. For each pound of aluminum cans he brought to the recycling center, he received $3. The function to represent the amount of money he earns can be represented by M(p) = 3p. To encourage more recycling, the recycling center changed its policy and decided to pay for recycling based on the weight of the cans – rounded to the nearest 10 pounds. So, if John brings in 11, 12, 13, or 14 pounds, he would only earn $30 - the amount of money for 10 pounds of recycling. But, if he brings in 15, 16, 17, 18, or 19 pounds, he will receive $40 – the amount of money for 20 pounds of recycling. However, the upper limit of recycling that could be deposited each month is 200 pounds. List a possible set of domain values for p for one month.

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Final answer:

A possible set of domain values for the weight of aluminum cans, p, for one month considering the recycling center policy change and the upper limit of recycling.

Step-by-step explanation:

The recycling center pays for recycling based on the weight of the cans, rounded to the nearest 10 pounds. If John brings in 11, 12, 13, or 14 pounds, he would only earn $30 - the amount of money for 10 pounds of recycling. But, if he brings in 15, 16, 17, 18, or 19 pounds, he will receive $40 - the amount of money for 20 pounds of recycling. However, the upper limit for recycling that can be deposited each month is 200 pounds.

Based on these conditions, a possible set of domain values for p (the weight of aluminum cans) for one month could be: 0, 10, 20, 30, 40, 50, 60, 70, 80, 90, 100, 110, 120, 130, 140, 150, 160, 170, 180, 190, 200.

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