Final answer:
The slope of the curve y^2(4-x) = x^2 at the point (3, -3) is 2.5, which is found using implicit differentiation.
Step-by-step explanation:
To find the slope of the curve described by the equation y^2(4-x) = x^2 at the point (x, y) = (3, -3), we need to use implicit differentiation. The slope at any point on a curve is given by the derivative dy/dx, which represents how y changes with respect to x. Since the relation is not that of a straight line, the slope will change at different points on the curve.
First, we apply the product rule for differentiation to the left side of the equation and get:
2y(dy/dx)(4-x) + y^2(-1) = 2x.
Then, we plug in the values x = 3 and y = -3:
-6(dy/dx)(1) - 9 = 6.
Solving for dy/dx, we find:
dy/dx = -(6 + 9) / -6.
dy/dx = 15 / 6 = 2.5.
So, when x = 3 and y = -3, the slope of the curve y^2(4-x) = x^2 is 2.5.
The complete question is: The relation y^2(4-x)=x^2 has a slope of when x=3 and y=-3 is: