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Peters well is 8 2/3 jewel has a well that is 11 feet deep what’s the ratio

User LiuChang
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Final answer:

The ratio of the depth of Peter's well (8 2/3 feet) to Jewel's well (11 feet) is found by converting Peter's well depth to an improper fraction (26/3) and then comparing it to Jewel's well depth, resulting in a ratio of 26:33.

Step-by-step explanation:

The question is asking to find the ratio of the depth of two wells. Peter's well is 8 2/3 feet deep and Jewel's well is 11 feet deep. First, we need to convert Peter's well depth into an improper fraction.

Peter's well: 8 2/3 = (8 × 3) + 2

= 24 + 2

= 26/3 feet

Now we have both depths in terms of feet and can compute the ratio:

Ratio = Depth of Peter's Well : Depth of Jewel's Well
= (26/3) : 11

To express this ratio in simplest form, we multiply both sides by 3 to get rid of the fraction:

Ratio = 26 : (11 × 3)
= 26 : 33

This ratio can't be simplified any further, so the final ratio of the depth of Peter's well to Jewel's well is 26:33.

User Johan Kullbom
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