Final answer:
The value of m for which (2,5) is a solution to the equation 2x+3y=m is 19. The value of k for which the point (k,-3) lies on the line 3x-y=6 is 1.
Step-by-step explanation:
To determine if (2,5) is a solution of the equation 2x+3y=m and to find the value of m, we must substitute x with 2 and y with 5 into the equation.
2(2) + 3(5) = m
4 + 15 = m
19 = m
Therefore, the value of m is 19, and the point (2,5) is indeed a solution to the equation.
To find the value of k for which the point (k,-3) lies on the line represented by 3x - y = 6, we substitute y with -3 and solve for x, which in this case is k.
3k - (-3) = 6
3k + 3 = 6
3k = 3
k = 1
The value of k for which the point (k, -3) lies on the line is 1.