Question

Chloe is coloring a poster to put up in her room. To make it more interesting, she is going to use whatever color

she picks out of a bag. Chloe puts six crayons in the bag -red, orange, yellow, green, blue, and violet. What is the
probability Chloe picks out a red and then an orange crayon without replacing the first crayon?

Answer 1

The probability of Chloe picking a red crayon and then an orange crayon without replacing the first one is 1/30, calculated by multiplying the individual probabilities of each event.

Step-by-step explanation:

The question at hand involves calculating the probability of Chloe picking a red crayon and then an orange crayon from a bag without replacing the first crayon. This is an example of a compound probability problem, where we are looking for the probability of two independent events happening in sequence.

To calculate this, we first find the probability of Chloe picking a red crayon. Since there are six crayons and one is red, this probability is 1/6. After she picks the red crayon and does not replace it, there are now five crayons left, including one orange crayon. So, the probability of then picking an orange crayon is 1/5.

The overall probability of both events occurring is the product of the two individual probabilities, which is (1/6) * (1/5) = 1/30. Therefore, the probability that Chloe picks out a red and then an orange crayon without replacing the first crayon is 1/30.