Question

Suppose that 27 g of each of the following substances is initially at 29.0 ∘c. what is the final temperature of each substance upon absorbing 2.30 kj of heat? silver

Answer 1

The final temperature of silver upon absorbing 2.30 kJ of heat from an initial temperature of 29.0 ℃ can be calculated using the specific heat capacity formula, q = mcΔT, where c is 0.235 J/g°C for silver. The final temperature is calculated by adding the change in temperature to the initial temperature.

Step-by-step explanation:

The question involves calculating the final temperature of silver upon absorbing 2.30 kJ of heat from an initial temperature of 29.0 ℃. To solve, we use the formula q = mcΔT, where q is the heat absorbed, m is the mass of the substance, c is the specific heat capacity, and ΔT is the change in temperature. Silver's specific heat capacity (c) is 0.235 J/g°C.

Step 1: Convert the heat absorbed from kilojoules to joules (since specific heat is in J/g°C). 2.30 kJ = 2300 J.

Step 2: Calculate ΔT using the formula: 2300 J = (27 g)(0.235 J/g°C)ΔT.

Step 3: Solve for ΔT: ΔT = 2300 J / (27 g × 0.235 J/g°C) = 2300 J / 6.345 J/°C = 362.50 °C.

Step 4: Add ΔT to the initial temperature to find the final temperature: Final temperature = 29.0 ℃ + 362.50 ℃.