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How much heat (in kJ) is needed to convert 10.0 grams of LiF(l) at 1673˚C to LiF(g) at 1673˚C?

User Jason Seah
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Final answer:

Without the latent heat of vaporization for lithium fluoride (LiF), it's not possible to calculate the precise amount of heat needed to vaporize 10.0 grams of LiF at 1673°C.

Step-by-step explanation:

To determine how much heat (in kJ) is needed to convert 10.0 grams of LiF(l) at 1673°C to LiF(g) at 1673°C, one must know the latent heat of vaporization for LiF. However, this information is not provided in the question or the reference information. Therefore, under these circumstances, a precise calculation cannot be made without that critical piece of data.

In general, the formula used to calculate the heat needed for phase change is Q = m × Lv, where 'Q' is the heat required, 'm' is the mass, and 'Lv' is the latent heat of vaporization. If the latent heat of vaporization were known for LiF, it would be straightforward to insert the mass of LiF and calculate the amount of heat required for the phase change from liquid to gas, assuming no change in temperature.

User Deepak Joshi
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