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During a neighborhood baseball game in a vacant lot, a particularly wild hit sends a baseball crashing through the pane of a second-floor window in a nearby building. the ball strikes the glass at , shatters the glass as it passes through, and leaves the window at with no change of direction. 0.147 kg 16.1 m/s 12.1 m/s what is the direction of the impulse that the glass imparts to the baseball? in the direction of the ball's motion opposite the direction of the ball's motion neither of these calculate the magnitude of this impulse (a positive number). impulse: n ⋅ s the ball is in contact with the glass for as it passes through. find the magnitude of the average force of the glass on the ball (a positive number).

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Final answer:

The impulse exerted by the glass on the baseball is in the opposite direction of the ball's motion, with a magnitude of -0.588 kg·m/s. The average force exerted by the glass cannot be calculated without knowing the time interval during which the force was applied.

Step-by-step explanation:

The direction of the impulse imparted by the glass to the baseball is opposite to the direction of the ball's motion. This is because the glass slows down the ball from an initial velocity of 16.1 m/s to 12.1 m/s. The magnitude of the impulse can be calculated using the formula Impulse = Δp = m(vf - vi), where 'm' is the mass of the baseball, 'vf' is the final velocity, and 'vi' is the initial velocity.

Given that the baseball's mass (m) is 0.147 kg, the initial velocity (vi) is 16.1 m/s, and the final velocity (vf) is 12.1 m/s, the impulse exerted on the baseball by the glass is:

Impulse = 0.147 kg x (12.1 m/s - 16.1 m/s) = -0.588 kg·m/s

Note that the impulse is negative, indicating that the force exerted by the glass is in the opposite direction to the motion of the baseball.

To find the magnitude of the average force exerted by the glass on the baseball, you need to know the time interval (Δt) during which the force was applied. Since this time is not provided, it cannot be calculated here.

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