Question

Consider the set of real numbers: {2⎯⎯√, 910, 2813, 6623%} . drag the numbers to order them from least (top) to greatest (bottom).

Answer 1

To arrange {√2, 9/10, 28/13, 66 2/3 %} from least to greatest, you convert each to decimal form. The order is 66 2/3 % (least), 9/10, √2, and 28/13 (greatest).

Step-by-step explanation:

To order the set of real numbers {√2, 9/10, 28/13, 66 2/3 %} from least to greatest, we need to compare their decimal equivalents.

1. √2 is approximately 1.414.
2. 9/10 is exactly 0.9.
3. 28/13 is approximately 2.154.
4. 66 2/3 % is equivalent to 0.666 (repeating).

Putting these decimals in order from least to greatest, we get:

1. 0.666 (66 2/3 %)
2. 0.9 (9/10)
3. √2
4. 2.154 (28/13)

Therefore, the correct order from least to greatest is 66 2/3 %, 9/10, √2, and 28/13.