Question

3. An average adult human weighs 75 kg. The average specific heat value for an average humanbody is 3.56 J/g. Calculate the total heat lost from an average human when the body temperaturedrops from 37 °C to 32.5 °C. 2 pts Show all your work

Answer 1

Answer: Q = -1335kJ ( exorthemic reaction)

Calculations:

Given the following parameters :

• Mass =75kg = 75*1000 = ,75000g

,

• Temperature final = 32.5 °C

,

• Temperature initial = 37.5°C

,

• Specific heat of human body ,(C,) = 3.56J/g

,

• We will use the formula Q = m*c*∆T to calculate total heat lost.

,

• Take note that this is an ,exorthermic reaction. ,therefore q <0

1. Calculate ∆T

`\begin{gathered} \Delta T=T_f-T_i \\ \text{ = ( 32.5 -37.5) }\degree C \\ \text{ =-5 }\degree C \end{gathered}`

• Therefore ∆T = -5°C

2. Calculate Q

`\begin{gathered} Q\text{ = mass}\cdot C\cdot\Delta T\text{ } \\ \text{ }=\text{ 75000g }\cdot\frac{3.56J}{g\text{.}\degree C}\cdot\text{ -5}\degree C \\ \text{ =-1335000J} \\ \text{ =-1335kJ } \end{gathered}`

• Therefore ; total heat lost from an average human when the body temperature drops from 37 °C to 32.5= -1335kJ