Question

A rectangle with an area of 240 in2 has a length 10 inches shorter than five times its width. which equation could be used to solve for the length of the rectangle?

a) 5w2 10w 240 = 05 w 2 10w 240 = 0
b) 5w2 − 10w 240 = 05 w 2 − 10w 240 = 0
c) 5w2 10w − 240 = 05 w 2 10w − 240 = 0
d) 5w2 − 10w − 240 = 0

Answer 1

The equation that could be used to solve for the length of the rectangle is option d) 5w² - 10w - 240 = 0.

Step-by-step explanation:

The equation that could be used to solve for the length of the rectangle is option d) 5w² - 10w - 240 = 0.

Let's represent the length of the rectangle as L and the width as W.

Given, the area of the rectangle is 240 in². So, we have LW = 240.

Also, the length is 10 inches shorter than five times the width, which can be written as L = 5W - 10.

Substituting L = 5W - 10 in the area equation, we get (5W - 10)W = 240. Simplifying this equation, we get 5W² - 10W - 240 = 0.