Question

Find the magnitude of the force the -10.00 μc charge exerts on the dipole. express your answer with the appropriate units.

Answer 1

The magnitude of the force exerted on the dipole by the -10.00 μC charge is 0.072 N, in the opposite direction of the electric field.

Step-by-step explanation:

The magnitude of the force exerted on a dipole by a charge can be calculated using the equation F = qE, where F is the force, q is the charge, and E is the electric field strength.

In this case, the charge is -10.00 μC and the electric field strength is given as 7.20 × 10⁵ N/C.

Plugging the values into the equation, we get F = (-10.00 × 10⁻⁶C)(7.20 × 10⁵ N/C) = -0.072 N.

Since force is a vector quantity, the magnitude of the force is equal to 0.072 N, with a negative sign indicating that the force is in the opposite direction of the electric field.