Question

2Square the binomial: (8y - 5)

Answer 1

`\begin{equation*} 64y^2-80y+25 \end{equation*}`

Given:

`(8y-5)^2`

When squaring a binomial, we can take note of the following:

`(a+b)^2=a^2+2ab+b^2`

From the given, we know that:

a = 8y

b = -5

With these, we have:

`\begin{gathered} (8y-5)^(2) \\ \Rightarrow(8y)^2+(2(8y)(-5))+(-5)^2 \\ \Rightarrow64y^2-80y+25 \end{gathered}`

Therefore,

`(8y-5)^2=64y^2-80y+25`