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If a 1500 kg car speeds up to 3.0 m/s and the gain in kinetic energy is 6750 j, then what amount of work is done on the car?

User Sarah Kemp
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1 Answer

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Final answer:

The amount of work done on the car is 6750 J.

Step-by-step explanation:

To calculate the work done on the car, we can use the work-energy theorem. The work done is equal to the change in kinetic energy of the car. Given that the gain in kinetic energy is 6750 J and the car speeds up to 3.0 m/s, we can use the formula:

Work = change in kinetic energy = 6750 J

Substituting the values into the formula: Work = (1/2) * mass * (final velocity^2 - initial velocity^2)

Work = (1/2) * 1500 kg * (3.0 m/s^2 - 0^2) = 6750 J

Therefore, the amount of work done on the car is 6750 J.

User Yfeldblum
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