Question

How many quarts of pure antifreeze must be added to 6 quarts of a 10​% antifreeze solution to obtain a 60​% antifreeze​ solution? question content area bottom part 1 enter your response here ​quart(s) of pure antifreeze must be added. ​(round to the nearest tenth as​ needed.)

Answer 1

Step-by-step explanation:

ingredients in = ingredients out

10% solution + 100% solution = 60% solution :

6 ( .10) + x (1.0) = (x+6)(.60)

.6 + x = .6x +3.6

.4x = 3

x = 7.5 quarts of pure Antifreeze

Answer 2

To get a 60% antifreeze solution, 7.5 quarts of pure antifreeze must be added to 6 quarts of a 10% antifreeze solution.

Step-by-step explanation:

To determine how many quarts of pure antifreeze must be added to 6 quarts of a 10​% antifreeze solution to obtain a 60​% antifreeze​ solution, we can set up the following equation:

Let x represent the quarts of pure antifreeze needed, then:

(Amount of pure antifreeze in solution) + (Amount of pure antifreeze added) = (Total amount of antifreeze in the final solution)

0.10(6) + x = 0.60(6 + x)

0.6 + x = 3.6 + 0.60x

x - 0.60x = 3.6 - 0.6

0.40x = 3.0

x = 3.0 / 0.40

x = 7.5 quarts

Thus, 7.5 quarts of pure antifreeze must be added. This calculation assumes that the volumes are additive.