Final answer:
The student's question is about calculating the final velocity and displacement of a 4.0 kg box being accelerated across a floor in a physics context, using principles of Newton's second law and kinematic equations.
Step-by-step explanation:
The student is asking a question related to Physics, specifically within the area of Newton's second law of motion and kinematics. In the scenario given, a box of mass 4.0 kg is accelerated from rest at a rate of 3.0 m/s2 for a duration of 5.0 seconds. To find answers related to the acceleration, the box's velocity after a certain time, and its displacement, one would apply the kinematic equations that relate acceleration, time, velocity, and displacement.
Example Calculations
To find the final velocity (v) of the box after the 5.0 s interval, one would use the kinematic equation v = u + at, where u is the initial velocity which is zero in this case, a is the acceleration, and t is the time.
For the displacement (s), the equation s = ut + ½at2 can be used, where all terms have their usual meaning.