Question

A blue car pulls away from a red stop-light just after it has turned green with a constant acceleration of 0.6 m/s 2 . a green car arrives at the position of the stop-light 4 s after the light had turned green. what is the slowest constant speed which the green car can maintain and still catch up to the blue car? answer in units of m/s.

Answer 1

The slowest constant speed that the green car can maintain and still catch up to the blue car is 1.2 m/s.

Step-by-step explanation:

To calculate the slowest constant speed that the green car can maintain and still catch up to the blue car, we can use the equations of motion. Let's assume that the blue car starts from rest at time t=0 and the green car arrives at the position of the stop-light at time t=4 s.

The distance traveled by the blue car can be calculated using the equation d = 0.5a(t^2), where a is the acceleration and t is the time. Plugging in the given values, we have d = 0.5 * 0.6 * (4^2). This gives us a distance of d = 4.8 m traveled by the blue car.

Now, we need to find the slowest constant speed that the green car can maintain and cover the same distance in 4 s. The formula to calculate distance is d = vt, where d is the distance, v is the velocity, and t is the time. Plugging in the given values, we have 4.8 m = v * 4 s. Solving for v, we get v = 1.2 m/s.