Question

A 5.00 cm tall object is placed 2.7 cm in front of a concave mirror and produces a real image that is 14.3 cm from the mirror. What is the magnification of the object?

Answer 1

We are asked to determine the magnification of a concave mirror. To do that we will use the following formula:

`M=(h_i)/(h_0)=-(d_i)/(d__0)`

Where:

`\begin{gathered} M=\text{ magnification} \\ h_0=\text{ height of the object} \\ h_i=\text{ height of the image} \\ d_0=\text{ distance of the object } \\ di=\text{ distance of the image} \end{gathered}`

We are given the following values:

`\begin{gathered} h_0=5cm \\ d_0=2.7cm \\ h_i=14.3cm \end{gathered}`

Therefore, we can use the following to determine the magnification:

`M=(h_i)/(h_0)`

Substituting the values:

`M=(14.3cm)/(5cm)`

Solving the operation:

`M=2.86`

Therefore, the magnification is 2.86