Question

2.1 x 10^8 /4.2x10^2

Answer 1

`(2.1X10^8)/(4.2X10^2)`

Since the question requires determining how many times 4.2 x 10^2 will be found in 2.1 x 10^8.

We simply have to divide 2.1 x 10^8 by 4.2 x 10^2

`(2.1)/(4.2)\text{ x}(10^8)/(10^2)`

Dividing the numerator and denominator and applying the laws of indices

`(1)/(2)X10^{8\text{ - 2}}`

=> 0.5 x 10^6

=> 5 x 10^5

Option C is correct