Question

I need a help!Please solve this question r2+200r-323 = 0

Answer 1

Given:

`r^2+200r-323=0`
`a=1\text{ ; b=200 ; c=-323}`
`r=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}`
`r=\frac{-200\pm\sqrt[]{200^2-4(1)(-323)}}{2(1)}`
`r=\frac{-200\pm\sqrt[]{400^{}+1292}}{2}`
`r=\frac{-200\pm\sqrt[]{400^{}+1292}}{2}`
`r=\frac{-200\pm\sqrt[]{1692}}{2}`
`r=\frac{-200\pm\sqrt[]{2^2*3^2*47}}{2}`
`r=\frac{-200\pm6\sqrt[]{47}}{2}`
`r=\frac{2(-100\pm3\sqrt[]{47})}{2}`
`r=-100\pm3\sqrt[]{47}`
`r=-100+3\sqrt[]{47}\text{ ,}-100-3\sqrt[]{47}`