Final answer:
Ozone (O3) added to a double bond between a 3' tertiary carbon and a 2' secondary carbon leads to the formation of 1 aldehyde from the secondary carbon and no reaction from the tertiary carbon. Option B, the formation of 1 aldehyde and 1 ketone, is correct if the tertiary carbon initially had two hydrocarbon groups to form a ketone.
Step-by-step explanation:
When ozone (O3) is added to a double bond to perform an ozonolysis reaction, the double bond will cleave, and we then consider the substituents attached to the carbons of the original double bond to predict the products. In this case, we have a double bond between a 3' carbon (tertiary) and a 2' carbon (secondary). According to the information given, an alcohol with its -OH group bonded to a carbon atom that is bonded to no or one other carbon atom will form an aldehyde, and an alcohol with its -OH group attached to two other carbon atoms will form a ketone. However, since the tertiary carbon cannot form the necessary C-H bond to create an alcohol, it will not form an oxidation product like an aldehyde or ketone.
Thus, the addition of ozone to this double bond will result in the formation of an aldehyde from the secondary carbon and no reaction on the tertiary carbon, which will be left as a carbonyl compound (ketone) if the tertiary carbon had two hydrocarbon groups originally attached. Therefore, the correct option is B: the formation of 1 aldehyde and 1 ketone.