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1 vote
Given the program:

1.a= (0.0,1.0,.25)
2.b=a+a
3.a=a+b[2]
4.x=a[-1]
What is the final value of x?

User Pzp
by
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1 Answer

7 votes

Final answer:

The final value of the variable x in the given Python program is .5, after performing tuple manipulation and indexing operations.

Step-by-step explanation:

The question seems to relate to a Python program, which initializes and manipulates a tuple assigned to variable a and finally seeks the value of variable x. Let's walk through the program step by step to find the answer:

  1. a is initially set to the tuple (0.0, 1.0, .25).
  2. Variable b is set to a + a, thus b becomes (0.0, 1.0, .25, 0.0, 1.0, .25).
  3. Then we update a by adding the third element of b to it. Since indexing in Python starts from 0, b[2] is .25, so a becomes (0.0, 1.0, .25 + .25) which simplifies to (0.0, 1.0, .5).
  4. Finally, we assign the value of x to the last element of a (denoted as a[-1]), which is .5.

Therefore, the final value of x is .5.

User Lukeyb
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