Final answer:
The speed of the box after 2 seconds is 8 m/s.
Step-by-step explanation:
Given that Eduardo pushed a box with an acceleration of 4 m/s2:
To find the speed of the box after 2 seconds, we can use the formula:
v = u + at
Where:
v is the final velocity (speed)
u is the initial velocity (speed)
a is the acceleration
t is the time taken
Since the box starts from rest and accelerates at a rate of 4 m/s2, the initial velocity (u) is 0 m/s. Plugging in these values into the formula:
v = 0 + 4 * 2
v = 8 m/s
Therefore, after 2 seconds, the speed of the box will be 8 m/s.