Question

The unknown mineral was placed in 100 mL of water. Once in the water, the volume went up to 165 mL. Then when the same object was dried, then massed on a balance. It had a mass of 292.5 grams. What is the density of the unknown mineral?

Answer 1

The density of the unknown mineral, found by dividing the mass (292.5 grams) by the volume (65 mL), is 4.5 g/mL.

Step-by-step explanation:

The density of an object is found by dividing its mass by its volume. The student wants to determine the density of an unknown mineral. Based on the given information, the mineral has a mass of 292.5 grams, and when placed in water, it increases the water volume from 100 mL to 165 mL, indicating that the volume of the mineral is 65 mL (165 mL - 100 mL).

The formula to calculate density (d) is d = m/v, where m stands for mass and v stands for volume. Plugging in the values we get:

d = 292.5 g / 65 mL

Doing the calculation:

d = 4.5 g/mL