Question

A ball is initially moving at 6 m/s up a ramp. The acceleration of the ball is -2 m/s/s down the ramp. What is the balls velocity after 10 seconds? (frame of reference + is up the ramp)

Answer 1

V = - 14 m/s

Step-by-step explanation:

Given:

V₀ = 6 m/s

a = - 2 m/s

t = 10 s

_____________

V - ?

According to the formula:

V = V₀ + a·t

V = 6 - 2·10 = - 14 m/s

(The ball rolls down an inclined plane)

Answer 2

Step-by-step explanation:

Comment

This is an example using a = (vf - vi)/t where

• a is the acceleration (-2 m/s^2
• vr is the final velocity (This is what we are solving for)
• t is the time = 10 seconds (in seconds )
• vi = 6 m/s (the initial velocity)

Solution

a = (vf - vi)/t Substitute the givens into the formula

-2m/s^2 = (vf - 6 m/s)/10 sec multiply both sides by 10

- 2 * 10 = 10(vf - 6) / 10 Combine

-20 = vf - 6 Add 6 to both sides

-20 + 6 = vf - 6 + 6

- 14 =vf

This means the ball is going down the ramp.