Final answer:
Using Newton's second law of motion and the kinematic equation, it was calculated that it took 3 seconds for a 150kg cart moving at 6m/s to stop with an applied force of 300N.
Step-by-step explanation:
The question asks how long it took for a 150kg cart moving at 6m/s to stop when a force of 300N is applied. To find the time it takes for the cart to stop, we need to use the formula derived from Newton's second law of motion, which is F = ma, where F is the force applied, m is the mass of the object, and a is the acceleration. Additionally, we use the kinematic equation which relates velocity, acceleration, and time: v = at.
First, we need to calculate the acceleration (a) using the force and the mass.
a = F/m = 300N / 150kg = 2m/s². The negative sign indicates that the force is acting in the opposite direction of the motion (deceleration). Next, we determine the time (t) it takes to stop the cart using the initial velocity (vi) and the acceleration.
vi = at, so t = vi/a = 6m/s / 2m/s² = 3s. Therefore, it took 3 seconds for the cart to come to a stop.