Question

"When dividing the polynomial p(x)= 3x3 - 10x2 + 13x -

6 by x-2, the remainder can be determined by evaluating
p(2). What is the value of this remainder?
p(2)= 5
p(2)= 0
p(2)= 3
p(2)= 4

Answer 1

The value of the remainder when dividing the polynomial p(x)= 3x^3 - 10x^2 + 13x -6 by x-2 is 4.

Step-by-step explanation:

To find the value of the remainder when dividing the polynomial p(x)= 3x^3 - 10x^2 + 13x -6 by x-2, we need to evaluate p(2).

Substituting x=2 into the polynomial, we get p(2) = 3(2)^3 - 10(2)^2 + 13(2) - 6 = 24-40+26-6 = 4.

Therefore, the value of the remainder is 4.