Final answer:
To react with 4.0 mol of O2 at STP, 44.8 L of N2 would be needed, based on the molar volume of a gas at STP and the stoichiometry of the reaction.
Step-by-step explanation:
The question asks about the volume of N2 needed to react with 4.0 mol of O2 at STP (standard temperature and pressure). We know that at STP, the molar volume of any gas is 22.4 L/mol. To find the volume of N2 needed, we must first determine the balanced chemical equation for the reaction between nitrogen and oxygen. Assuming we are forming nitrogen dioxide (NO2), the balanced equation is 2N2 + 4O2 → 4NO2. According to this stoichiometry, 1 mole of N2 reacts with 2 moles of O2. Since we have 4 moles of O2, we require 2 moles of N2. Therefore, the volume of N2 required at STP is 2 moles × 22.4 L/mol = 44.8 L.