Final Answer:
The third term in the sequence defined by the recursive rule f(n) = f(n-1)/2 +5 is 8.5.
Step-by-step explanation:
Given recursive rule:
f(n) = (f(n-1)/2) + 5
Given first term:
f(1) = 4
Using the recursive rule to find f(2):
f(2) = (f(1)/2) + 5
f(2) = (4/2) + 5
f(2) = 2 + 5
f(2) = 7
Using the recursive rule again to find f(3):
f(3) = (f(2)/2) + 5
f(3) = (7/2) + 5
f(3) = (7 + 10)/2
f(3) = 17/2
f(3) = 8.5
Therefore, the third term (f(3)) in the sequence is 8.5.
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Complete Question
The recursive rule for a sequence is f(n) = f(n-1)/2 +5. The first term is 4. What is the third term?
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