Final answer:
The block accelerates at 0.50 m/s², and the net force acting on it is 2.2 N, calculated using Newton's second law of motion and the kinematics equation for acceleration.
Step-by-step explanation:
To determine the acceleration and net force acting on a 4.4-kg block which starts from rest and reaches a velocity of 0.25m/s in 0.50s, we use the following formulas from Newton's second law of motion and the basic kinematics.
- First, calculate the acceleration (a) using the kinematic equation: a = (v_f - v_i) / t, where v_f is the final velocity, v_i is the initial velocity (which is 0 since the block starts at rest), and t is the time taken.
- Plug in the given values to find acceleration: a = (0.25 m/s - 0) / 0.50 s = 0.50 m/s².
- To find the net force (F_net), use Newton's second law: F_net = m * a, where m is the mass of the block.
- Substitute the values of mass and acceleration to get the net force: F_net = 4.4 kg * 0.50 m/s² = 2.2 N.
The block's acceleration is 0.50 m/s², and the net force acting on it is 2.2 N.