Question

An airplane increases its speed at an average rate of 15 m/s^2. If the airplane accelerates from 114.5 m/s to 143.2 m/s, the time required to do so would be:

A. 1.83 s
B. 2.00 s
C. 5.80 s
D. 7.64 s

Answer 1

To find the time required for the airplane to accelerate from 114.5 m/s to 143.2 m/s, we can use the equation: Final velocity = Initial velocity + (Acceleration × Time). Substituting the given values and solving for Time, we find that the time required is approximately 1.83 seconds.

Step-by-step explanation:

To find the time required for the airplane to accelerate from 114.5 m/s to 143.2 m/s, we can use the equation:

Final velocity = Initial velocity + (Acceleration × Time)

Since the airplane is accelerating uniformly, the average acceleration can be used.
Given:
Initial velocity (u) = 114.5 m/s
Final velocity (v) = 143.2 m/s
Average acceleration (a) = 15 m/s²

Substituting the values into the equation, we have:
143.2 m/s = 114.5 m/s + (15 m/s² × Time)

Solving for Time:

Time = (143.2 m/s - 114.5 m/s) / 15 m/s²

Time = 1.83 seconds

Therefore, the time required for the airplane to accelerate from 114.5 m/s to 143.2 m/s is approximately 1.83 seconds.