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If chlorine gas occupies a volume of 1.50 L at a pressure of 620.8 torr, what volume will it occupy at a pressure of 760.0 atm?

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Final answer:

To find the final volume of chlorine gas at a pressure of 760.0 atm, we can use Boyle's law. Using the formula P1V1 = P2V2, where P1 is the initial pressure, V1 is the initial volume, P2 is the final pressure, and V2 is the final volume, we can calculate that the final volume of chlorine gas is approximately 1.23 L.

Step-by-step explanation:

To solve this problem, we can use Boyle's law, which states that the volume of a gas is inversely proportional to its pressure at a constant temperature. In other words, as the pressure increases, the volume decreases, and vice versa. The formula for Boyle's law is:

P1V1 = P2V2

Where P1 and V1 are the initial pressure and volume, and P2 and V2 are the final pressure and volume.

In this case, we know that the initial volume is 1.50 L and the initial pressure is 620.8 torr. Let's use the formula to find the final volume:

P1V1 = P2V2

(620.8 torr)(1.50 L) = (760.0 atm)(V2)

Solving for V2:

V2 = (620.8 torr)(1.50 L) / (760.0 atm)

V2 ≈ 1.23 L

User David Rutten
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